A car initially at rest starts moving with an acceleration of 4ms^-2.The time in which it picks up a velocity of 72 ms^-1 is
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Answered by
40
u = 0m/s.
a= 4m/s^2.
v= 72 m/s .
By | eq of motion ,
v = u + at
72 = 0 + 4 × t
t = 72/ 4
t = 18 second .
a= 4m/s^2.
v= 72 m/s .
By | eq of motion ,
v = u + at
72 = 0 + 4 × t
t = 72/ 4
t = 18 second .
Answered by
18
Given,
U = 0
a= 4 m/s2
v= 72 m/s
By equation 1
v=u+at
72= 4t
T = 18 sec.
U = 0
a= 4 m/s2
v= 72 m/s
By equation 1
v=u+at
72= 4t
T = 18 sec.
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