Question

a car initially at rest starts to moves with a velocity 10 m/ s and travels a distance 200 m find acceleration and time taken
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Answer 1

Explanation:

Given:

• Initial velocity (u) = 0 m/s
• Final velocity (v) = 10 m/s
• Distance traveled by the car (s) = 200 m

To find:

• Acceleration (a) = ?
• Time taken (t) = ?

Solution:

▪︎We know, Newton's third kinematic equation i.e, v^2 = u^2 + 2as.

For the value of acceleration, put the given values in the 3rd equation of motion.

==> (10)^2 = (0)^2 + 2 × a × 200

==> 100 - 0 = 400 × a

==> 100/400 = a

==> 0.25 m/s^2 = a

》Acceleration = 0.25 m/s^2

▪︎ We know, Newton's first kinematic equation of motion i.e, v = u + at.

For the value of time taken by the car, put the values in the 1st equation of motion.

==> 10 = 0 + 0.25 × t

==> 10 - 0 = 0.25 × t

==> 10/0.25 = t

==> 40 s = t

》Time taken = 4 seconds

Hence, we got the required ans.

Hope it helped you dear...