Question

A car initially moving with a speed of 10m/s is uniformly accelerated for 20 seconds. Value of acceleration is 4 m/s. What will be its velocity after 20 seconds and what distance it will cover in 20 sec?

Answer 1

Explanation:

given that,u=10m/s

t=20s

a=4m/s^2

final velocity,v=u+at

=10+(4*20)

=90 m/s

from 3rd eqn of motion,we know that

v^2=u^2+2as

(90)^2=(10)^2+2*4*s

8100=100+8s

8s=8000

s=1000 m

so it will cover 1000 m or 1 km in 20s