A car initially moving with a velocity of 20 m/s is applying break and comes to
rest after moving through a distance of 0.50 m. Calculate the total retardation
developed in the motion?
Answers
Answered by
0
Answer:
use the formula of acceleration and then change the answer in negative or positive or visoversa
Answered by
0
Answer:
-400m/s²
Explanation:
third equation of motion:a=vf²-vi²/2s
0²-20²/2(0.5)
-400/1
-400m/s²
Similar questions