Question

A car, initially traveling at a speed of 35 m/s, increases speed at a constant rate of 3.5m/s2 for 4.5 seconds. What is the total distance traveled by the truck during this 4.5-second time interval?

Answer 1

Explanation:

This means that the initial velocity is zero and the final velocity is 60 miles per hour (26.82 meters per second). In other areas of the world, it's 0 to 100 km/h

Answer 2

Answer:

$\bigstar{\bold{Distance\:travelled=193\:m}}$

Explanation:

$\Large{\underline{\underline{\bf{Given:}}}}$

• Initial velocity (u) = 35 m/s
• Acceleration (a) = 3.5 m/s²
• Time taken (t) = 4.5 s

$\Large{\underline{\underline{\bf{To\:Find:}}}}$

• Distance travelled (s)

$\Large{\underline{\underline{\bf{Solution:}}}}$

→ We need to find the distance travelled by the car.

→ By the second equation of motion, distance travelled is given by,

  s = ut +  1/2 × a × t²

→ Substituting the datas we get,

  s = 35 × 4.5 + 1/2 × 3.5 × 4.5 × 4.5

  s = 157.5 + 1/2 × 70.875

  s = 157.5 + 35.44

  s = 193 m

→ Hence distance travelled by the car = 193 m

  $\boxed{\bold{Distance\:travelled=193\:m}}$

$\Large{\underline{\underline{\bf{Notes:}}}}$

→ The three equations of motion are:

• v = u + at
• s = ut + 1/2 × a × t²
• v² - u² = 2as