Question

A car initiatly moving at a speed of 32m/s slows down for a 2m/s2 for adistance of 60m. What is the cars speed after covering the distance

Answer 1

Answer:

• Initial velocity (u) = 32 m/s

• Acceleration (a) = 2 m/s²

• Distance (s) = 60 m

• Final velocity (v) = ?

By applying third kinematical equation of motion we have:

=> (v)² - (u)² = 2as

=> (v)² = (u)² + 2as

=> (v)² = (32)² + 2(2)(60)

=> (v)² = 1024 + 240

=> (v)² = 1264

=> v = √(1264)

=> v = 35.55 m/s

Answer 2

Answer:28m/sec

Explanation:v^2 - u^2 = 2as

u = 32m/sec

a = -2m/s^2 (-ve because it slows down)

s = 60

v = ?

v^2 -32^2 = -240

v^2 = -240+1024

v^2 = 784

v = 28