A car intially at rest moving with an acceleration of 4ms
Answers
Answer:
Answer:
\green{\therefore{\text{Time\:taken=18\:sec}}}∴Timetaken=18sec
\orange{\bold{\underline{\underline{Step-by-step\:explanation:}}}}
Step−by−stepexplanation:
• In the given question information given about A car initially at rest starts moving with an acceleration of 4ms^2.
• We have to find Time taken to attain velocity of 72 m/s.
\begin{gathered} \green{\underline\bold{Given :}} \\ :\implies \text{Initial\:velocity(u)=0 m/s} \\ \\ :\implies \text{Final \: velocity (v)= 72 \:m/s} \\ \\ :\implies \text{Acceleration= 4 m/ s}^{2}\\ \\ \red{\underline \bold{To \: Find : }} \\ :\implies \text{Time\:taken(t)= ?}\end{gathered}
Given:
:⟹Initialvelocity(u)=0 m/s
:⟹Final velocity (v)= 72 m/s
:⟹Acceleration= 4 m/ s
2
ToFind:
:⟹Timetaken(t)= ?
• According to given question :
\begin{gathered} \bold{Using \: first \: equation \: of \: motion : } \\ : \implies v = u + at \\ \\ : \implies 72= 0 + 4 \times t \\ \\ : \implies t \times 5 = {72} \\ \\ : \implies t= \frac{72}{4} \\ \\ \green{ : \implies {\text{t = 18\: sec}}}\end{gathered}
Usingfirstequationofmotion:
:⟹v=u+at
:⟹72=0+4×t
:⟹t×5=72
:⟹t=
4
72
:⟹t = 18sec
Explanation: