A car intially at rest, picks up a velocity of 72km/h in 20s.if the mass of car is 1000kg.calculate the force developed by its engine and the distance covered by the car in 20s
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Answer:
1000N
Explanation:
t= 20sec
u= o
v= 72× 5/ 18
20mpersecond
a= v- u/ t
20-0/20
1 m/ sec2
force =ma
1000× 1
1000N
distance = ut + 1/2 at2
0×20+1/2×1×20square
1/2×400
200m
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