A car is 250 metres behind the bus. The car and bus are moving with the speed of 60 kmph and 35 kmph respectively. The car will be ahead of bus by 250 metres in:
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Okay Now relative velocity kicks in( when using relative velocity one object is totally stopped and others are observed through it's perspective )
Relative velocity of Car with respect to Bus is 60-35= 25 KMPH
This is the speed the Bus will See the Car approaching at
Now if we see from the frame of the Bus At first it was 250 m behind and at final POS it was 250 m in front
Relative Disp = 500 m
25 KMPH = 125/18 m/s
as speed is constant and a= 0
S= ut
500 = 125/18 *t
4*18=t
t= 72 sec
Relative velocity of Car with respect to Bus is 60-35= 25 KMPH
This is the speed the Bus will See the Car approaching at
Now if we see from the frame of the Bus At first it was 250 m behind and at final POS it was 250 m in front
Relative Disp = 500 m
25 KMPH = 125/18 m/s
as speed is constant and a= 0
S= ut
500 = 125/18 *t
4*18=t
t= 72 sec
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