Question

A car is accelarated at 4m/s² has a velocity of 10 m/s when it cross a lamp post . The distance travelled by the car in 8th second after crossing the lamp post is

Answer 1

GIVEN:-

• $\mathcal{Acceleration = 4m/s}$
• $\mathcal{Initial\:Velocity = 10m/s}$
• $\mathcal{Time\:Taken= 8s}$

TO FIND:-

• The Distance travelled by the car in 8th second after crossing the lamp post.

FORMULAE USED:-

• ${\large{\boxed{\mathbb{S_nth =u +\dfrac{a}{2}(2n-1)}}}}$

Where,

S = Distance

u = Initial Velocity

n = Time

a = Acceleration.

Now,

$\implies\mathcal{S = u + \dfrac{a}{2}(2n-1)}$

$\implies\mathcal{ S = 10 + \dfrac{4}{2}(2(8)-1)}$

$\implies\mathcal{S = 10 + 2 (15)}$

$\implies\mathcal{ S = 40m}$.

Hence, The Distance travelled by car is 40m.