a car is accelarating uniformly between two check points in 60 meter apart the time taken between two checkpoint in 4 second if the initial speed is 5m/s find the speed and accelaration of car
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Answered by
1
Answer:
a=5
vfinal=25
Explanation:
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Answered by
1
Answer:
From kinematics equation S=ut+
2
1
gt
2
; where S=60m; t=6s
60=u×6+
2
1
a×6
2
...(i)
and the velocity at second point is given as v=15m/s
From kinematics equation v=u+at
15=u+a×6....(ii)
solving equation (i) and (ii)
a=
3
5
m/s
2
;u=5m/s
2
The car starts from rest with uniform acceleration
Using kinematics equation
v
2
=u
2
+2aS; v=5m/s;u=0m/s;a=
3
5
m/s
2
⇒25=0+2×
3
5
×S
S=7.5m
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