Question

A car is accelerated uniformly from 36 km/hr to 54 km/hr in 10 sec. Find the acceleration and the distance traveled by the car during this interval of time

Answer 1

Here you Go,

Hope this helps!

Answer 2

Question :-

A train accelerates from 36 km/hr to 54 km/hr in 10 second. find acceleration and the distance travelled by car.

Answer:

⠀⠀

• Accleration = 5m/s²

• Distance = 125m.

⠀⠀

Given:

u) = 36 km/hr

v) = 54 km/hr⠀⠀

t) = 10 s

Here ,

u = Initial velocity

v = Final velocity

t = Time

⠀⠀

To find:

⠀What is the acceleration and distance ?

Solution :⠀⠀

Applying the formula :-

A. = ∆v/∆t

∆v = a × ∆t

Putting the values :- ⠀⠀

∆v = 54 – 36 = 18 km/hr.

Converting km /hr into m/s.

∆v = 18 × 1000/3600 m/s

= 5m/s

Therefore A = 5m/s²

Now , using second equation of motion :- ⠀⠀

$s$ = ut + 1/2at²

Here ,

s = Distance

u = Initial velocity

v = Final velocity

t = Time

Again putting values :-)

s = 10 × 10 + 1/2 × 5 × 10²

s = 125 m .

Hence ,

Acceration = 5m/s².

distance = 125 m .

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