Question

A car is accelerates uniformely from 18km/hr to 36km/hr within a distance of 15m. the uniform accelaration of the car is.....

Please answer stepwise​..​

Answer 1

Heya there,

U = 18km/sec

= 5m/s

V= 36 km/s

= 10m/sec

S = 15m

V^2 - U^2 = 2as

100 - 25 = 2as

75 = 2as

a = 75 / 2×15

a = 75 / 30

a = 2.5 m /s^2

Answer 2

$\mathsf{\huge{\boxed{Answer =2.5m/s^2}}}$

Step-by-step Explanation

Here we will use 3rd equation of motion :-

$v^2-u^2 = 2as$

____________________________

Now, ATQ

Initial velocity (u) = 18 km/hr

Convert it to m/s by multiplying by 5/18

( by solving 1000/3600)

$18 * 5/18$

= 5 m/s......(i)

Final velocity (v) = 36 km/hr

» Convert it also to m/s

$36*5/18$

=10m/s..........(ii)

Distance (s) = 15 m........ (iii)

Put all these values in equation

» We , will get

$(10)^2-(5)^2=2*a*15$

100-25/30=a

a= 75/30

$a= 2.50m/s^2$

So your answer is $<strong>2</strong><strong>.</strong><strong>5</strong><strong>m</strong><strong>/</strong><strong>s</strong><strong>^</strong><strong>2</strong>$