A car is accelerating uniformly as it passes two checkpoints that are 80m apart. The
time taken between checkpoints is 8s, and the car’s speed at the first checkpoint is 5m/s.
Find the car’s acceleration and its speed at the second checkpoint
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Answer:
acceleration is 5/4 m/s^2 and speed at 2nd checkpoint is 15 m/s
Explanation:
Let acceleration be a m/s^2.
initial velocity(u) = 5 m/s.
Displacement(s) = 80m
Time taken(t) is 8s
s = ut + 1/2 at ^2
substitute the values and solve the equation ,u get a = 80/64 = 5/4
let v be final velocity
v = u + at
solve u get v = 15 m/s
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