Question

a car is accelerating uniformly from 36km/h in 10 seconds . find a)the acceleration b) the distance travelled by the car during this time interval ?

Answer 1

acceleration =
$\frac{change \: in \: velocity}{time \: taken}$
change=final velocity -initial velocity
=36km/h=10m/s

acceleration =
$\frac{10m {s}^{ - 1} }{10s} \\ = 1m {s}^{ - 2}$
distance=speed×time
=10m/s×10s=100m



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