Question

a car is accerarated from 36km/h to 90 km/h in 3 sec find acceraration and distance covered

Answer 1

Answer:

u=36km/h

=10m/s

v=90km/h

=25m/s

t=3sec

a=(v-u)/t

=15/3

=5m/s^2

v^2-u^2=2as

625-100=10s

s=525/10

=52.5m

Answer 2

Answer:

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Explanation:

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