Question

A car is being driven at a speed of 40 m/s when brakes are applied to bring it to rest in 10 s. The acceleration produced in the case will be:​

Answer 1

Explanation:

QUESTION→

A car is being driven at a speed of 40 m/s when brakes are applied to bring it to rest in 10 s. The acceleration produced in the case will be:

ANSWER→

According to the question, we can conclude the following-

Initial velocity u = 40 m/s

Final velocity v = 0 (As the car stops at last)

Time taken t = 20 seconds

Now, we can calculate the deceleration (opposite of acceleration)

As acceleration = Change in velocity (final - initial)/time

a = (v - u) / t

= (0 - 40)/20

= - 2m/s (deceleration)

Now

S = Distance travelled while the deceleration took place

S = u*t + 1/2 * a* t^2

= 40 * 20 + 1/2 * (-2) * (20)^2

= 800 - 400

= 400 metres.

I HOPE ITS HELPFUL

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Answer 2

Answer:

see the attachment...