Physics, asked by aaditya00724, 2 days ago

a car is being driven by a force of 5 x 10¹⁰ N. When travelling at a speed of 10 m/s it takes 2 minutes for this car to reach the river side. Calculate the work done.​

Answers

Answered by ExᴏᴛɪᴄExᴘʟᴏʀᴇƦ
77

Given

  • F = 5 x 10¹⁰ N
  • T = 2 minutes
  • Speed = 10 m/s

To Find

  • Work

Solution

☯ Speed = D/T & Work = Force × Displacement

  • We'll use th first formula to find the distance covered, substitute in the second formula to get the work done

━━━━━━━━━━━━━━━━━━━━━━━━━

✭ According to the Question :

➞ S = D/T

➞ 10 = D/(2×60)

10 × 120 = 1200 m

━━━━━━━━━━━━━━━━━━━━

So then the work done is,

➞ W = F × d

➞ W = 5 x 10¹⁰ × 1200

➞ W = (5×12) × (10¹⁰×10²)

➞ W = 60 × 10¹²

∴ The work done is 60 × 10¹² J


Saby123: Nice!!!!
mddilshad11ab: Great¶
Answered by MяMαgıcıαη
78

Question:

  • A car is being driven by a force of 5 × 10¹⁰ N. When travelling at a speed of 10 m/s it takes 2 minutes for this car to reach the river side. Calculate the work done.

Answer:

  • Work done is 60 × 10¹² J.

Step-by-step explanation:

\large{\underline{\underline{\red{\bf{G}\text{iven\::-}}}}}

  • Force = 5 × 10¹⁰ N
  • Speed = 10 m/s
  • Time = 2 minutes

\large{\underline{\underline{\blue{\bf{T}\text{o}\:\bf{F}\text{ind\::-}}}}}

  • Work done?

\large{\underline{\underline{\purple{\bf{S}\text{olution\::-}}}}}

Formulae used in this question ::

\bullet\:\large{\boxed{\bf{Distance = Speed\:\times\:Time}}}

\bullet\:\large{\boxed{\bf{Work\:done = Force\:\times\:Distance}}}

Firstly converting time into seconds from minutes. As we know that 1 minute = 60 seconds. Therefore ::

\\ :\implies\:\sf 2\:minutes = \big(2\:\times\:60\big)\:seconds

\\ :\implies\:\bf 2\:minutes = 120\:seconds

Hence, time in seconds is 120 seconds.

Now finding distance by using formula of distance ::

\\ :\implies\:\sf Distance = Speed\:\times\:Time

Plugging all values in formula we get,

\\ :\implies\:\sf Distance = 10\:\times\:120

\\ :\implies\:\bf Distance = 1200\:m

Hence, distance is 1200 m.

Now finding work done by using formula of work done ::

\\ :\implies\:\sf Work\:done = Force\:\times\:Distance

Plugging all values in formula we get,

\\ :\implies\:\sf Work\:done = \big(5\:\times\:10^{10}\big)\:\times\:1200

We can write it as,

\\ :\implies\:\sf Work\:done = 5\:\times\:10^{10}\:\times\:12\:\times\:100

\\ :\implies\:\sf Work\:done = 5\:\times\:10^{10}\:\times\:12\:\times\:10^2

\\ :\implies\:\sf Work\:done = 5\:\times\:12\:\times\:10^{10}\:\times\:10^2

\\ :\implies\:\sf Work\:done = 60\:\times\:10^{(10\:+\:2)}

\\ :\implies\:\bf Work\:done = 60\:\times\:10^{12}\:J

Hence, work done is 60 × 10¹² J.

\rule{200}7


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