Question

A car is crossing point A at time t=0 with velocity of 5ms^-1 .The distance in between the points A and B is 100m.If the car is moving with constant acceleration,then the time taken by the car to just cross the midpoint of AB is​

Answer 1

Answer:

AB = 100 m Let x be the midpoint of the AB So AX = 50 m

using newton's third law of motion

\frac{v^2-u^2}{2s} = a

2s

v

2

−u

2

=a

here, v = 5\sqrt{7}5

7

m/s u = 5 m/s and s = 100 m

put the value and we get a = 0.75 m/s^2

again put this equation of the midpoint

here, a= 0.75 m/s ( a = constant) u = 5m/s s = 50 m v =?

put the above values and we get

v = 10 m /s

then using newton's first law

v = u +at

here v = 10m/s u= 5m/s a= 0.75 m/s

we get t = 20/3 sec,

Hope it helps!!