A car is crossing the road-turn with a speed of 10 m/s. if the coefficient of friction is 0.5, then radius of turn on the car is?? g=10m/s²
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V=10m/s , U=0.5.
V max=√ugr.
R=V2/ug
=100/0.5 ad =20...
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20 is ur answer....
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