A car is going at a speed of 6 m/s when it encounters
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Answered by
3
Answer:
acceleration down the slope
a=gsinθ−μgcosθa=gsinθ−μgcosθ
a=10sin30−(0.5)(10)cos30a=10sin30−(0.5)(10)cos30
=5−4.33=5−4.33
a=0.67m/s2a=0.67m/s2
Minimum speed while reaching the bottom
v2=u2+2asv2=u2+2as
v2=62+2(0.67)(15)v2=62+2(0.67)(15)
=56.1=56.1
v=7.46m/s
Answered by
0
Answer:
ecounter wht???
Step-by-step explanation:
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