Math, asked by aayushmaanverma7131, 10 months ago

A car is going at a speed of 6 m/s when it encounters

Answers

Answered by Anonymous
3

Answer:

acceleration down the slope

a=gsinθ−μgcosθa=gsin⁡θ−μgcos⁡θ

a=10sin30−(0.5)(10)cos30a=10sin⁡30−(0.5)(10)cos30

=5−4.33=5−4.33

a=0.67m/s2a=0.67m/s2

Minimum speed while reaching the bottom

v2=u2+2asv2=u2+2as

v2=62+2(0.67)(15)v2=62+2(0.67)(15)

=56.1=56.1

v=7.46m/s

Answered by sasmitcl2
0

Answer:

ecounter wht???

Step-by-step explanation:

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