Question

A car is going is east with a velocity 10m/s to the passanger in the car . a train appears to move west with a velocity 15m/s . what is actual velocity of train

Answer 1

When two bodies comes closer to each other we add their velocities similarly when two bodies moves in the same direction we minus the velocity of one from other..in this case the aperant velocity i.e(15m/s)
Which is the sum of the velocity of the car and the train ..so we can get the velocity of train by
Vav=V1+V2
V2=Vav-V1
V2 =15-10
V2=5m/s

Answer 2

Hope this will help.

The car is going in east direction with velocity of 10m/s.

Thus Vc=10m/s.

The train moving in west .

The velocity of train with respect to car is 15m/s.

Thus Vtc=15m/s.

Therefore,
Vtc=Vt-Vc

15=-Vt-10 because the velocity of train is in opposite direction.

Therefore, Vt= -5m/s

Thus the velocity of train is 5m/s in opposite direction.