Question

A Car is initially at rest starts moving with a uniform acceleration of 0.5m/s² and moves with it for 5 minutes find its velocity after 5 min and and distance Traveled in 5 mins .

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Answer 1

⇝ Given :-

• A Car is initially at rest starts moving with a uniform acceleration of 0.5m/s² and moves with it for 5 minutes

⇝ To Find :-

• Final Velocity and Distance traveled.

⇝ Solution :-

❒ Converting Time in Seconds :-

We Have,

$\text{Time= 5 mins}$

$= \rm( 5 \times 60)second$

$\red{:\longmapsto \text{Time = 300 \:s}}$

Here,

• Initial Velocity = u = 0 m/s

• Time Taken = t = 300 s

• Acceleration = a = 0.5 m/s²

1 》 Calculating Final Velocity :-)

Let Final Velocity of Car be = v m/s

❒ We Have 1st Equation of Motion as :

$\large \bf \red \bigstar \: \: \orange{ \underbrace{ \underline{v = u + at}}}$

⏩ Applying 1st Equation of Motion ;

$:\longmapsto \rm v = 0 + 0.5 \times 300$

$:\longmapsto \rm v = 0.5 \times 300$

$\purple{ \Large :\longmapsto  \underline {\boxed{{\bf v = 150} }}}$

Therefore,

$\large\underline{\pink{\underline{\frak{\pmb{\text Final \: \text Velocit\text y = 150\: m/s }}}}}$

2 》Calculating Distance Traveled :-)

❒ We Have 2nd Equation of Motion as :

$\large \bf \red \bigstar \: \: \orange{ \underbrace{ \underline{s=ut+\dfrac{1}{2}at^2}}}$

⏩ Applying 2nd Equation of Motion :

$:\longmapsto \rm s = 0 \times 300 + \frac{1}{2} \times 0.5 \times 300 {}^{2}$

$:\longmapsto \rm s = 0 + \frac{1}{2} \times 0.5 \times 90000$

$\purple{ \large :\longmapsto  \underline {\boxed{{\bf s = 22500 \: m} }}}$

Therefore,

$\large\underline{\pink{\underline{\frak{\pmb{ Distance  \text Traveled = 22.5 \: \text km }}}}}$

Answer 2

Given :-

A Car is initially at rest starts moving with a uniform acceleration of 0.5m/s² and moves with it for 5 minutes

To Find :-

find its velocity after 5 min and distance Traveled in 5 mins.

Solution :-

We know that

1 min = 60 sec

5 min = 5 × 60

5 min = 300 sec

Now

v = u + at

v = 0 + 0.5 × 300

v = 0 + 150

v = 150 m/s

Now

v² - u² = 2as

(150)² - (0)² = 2(0.5)(s)

22500 - 0 = 1s

22500 = s