Question

A car is initially moving at 18km /h and uniformly accelerate at the rate of 5m/s for 8 second calculate (i) the final velocity and (ii) the distance covered by the car

Answer 1

Answer:

The final velocity is 45m/s

The distance covered by the car is 60m

Explanation:

inutial velocity of the car(u)=18km/h

=18 x 1000m/3600=5m/s

final velocity(v)=?(we have to find)

accelartion of the car(a)=5m/s^2

time taken to accelarate(t)=8 second

using the formula

$v = u + at$

$v = 5m \: per \: second + (5m \: per \: second {}^{2} )(8second)$

$v =45m \: per \: second$

to find the distance covered by the car

$\underline{s=ut+1/2at^2}$

$s = ut + \frac{1}{2} at {}^{2}$

$s =( 5m \: per \: second)(8 \: second) + \frac{1}{2} (5m \: per \: second {}^{2} )(8 \: second) {}^{2}$

$s = 60m$