Physics, asked by Edward1508, 9 months ago

A car is lifted by a hydraulic jack that consists of two pistons. The diameter of the larger piston is 2 m and that of the smaller piston is 50 cm. If the force applied on the smaller piston is 240 N, find the weight of the car.

Answers

Answered by help7oo645o984
5

Answer:

240/(0.25^2) = wt./ 1^2

wt = 240/0.0625

= 3840 N

Answered by sangeethadale53
5

ANSWER:2M=200CM

RADIUS OF LARGE PISTON=200/2=100CM

AREA(1) =πr^2=π×50^2=2500πCM^2

DIAMETER OF SMALLER PISTON= 50CM

RADIUS=50/2=25

AREA(2)= πR^2

=625πF

=W×A(2)/A(1)

=F=W×625π/2500π

=F=W/20

SO MINIMUM FORCE IS W/20

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