A car is marked at Rs 300000. The dealer allows successive discounts of 6% , 4% and 5/2 on it. What is the net selling price
Answers
Answered by
91
1st discount
6% of 300000 = 6/100×300000
= 18000
SP=MP-DISCOUNT
=300000-18000
=282000
2nd discount
4% of 282000 = 4/100×282000
= 11280
sp = mp - discount
= 282000-11280
= 270720
3rd discount
5/2 of 270720 = ( 5/2 ÷ 100 ) × 270720
= ( 5/2 × 1/100) × 270720
= 1/40 × 270720
= 6768
sp = mp - discount
= 270720 - 6768
= 263952
6% of 300000 = 6/100×300000
= 18000
SP=MP-DISCOUNT
=300000-18000
=282000
2nd discount
4% of 282000 = 4/100×282000
= 11280
sp = mp - discount
= 282000-11280
= 270720
3rd discount
5/2 of 270720 = ( 5/2 ÷ 100 ) × 270720
= ( 5/2 × 1/100) × 270720
= 1/40 × 270720
= 6768
sp = mp - discount
= 270720 - 6768
= 263952
Answered by
9
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