Question

A car is mo ing with the car intial velocity 15m/s car stopped after 5 sec by application of breaks find the retardatio

Answer 1

Answer:

Explanation:

Let’s review the 4 fundamental kinematic equations of motion for constant accelerate

s = ut + ½at^2 …. (1)

v^2 = u^2 + 2as …. (2)

v = u + at …. (3)

s = (u + v)t/2 …. (4)

where s is distance, u is initial velocity, v is final velocity, a is acceleration and t is time.

In this case, we know u = 15m/s, v = 0, t = 5s and we want to find a, so we use equation (3)

v = u + at

0 = 15 + 5a

a = -15/5 = -3

The acceleration is -3m/s^2, and the negative sign indicates that it is a retardation.