A car is move at a speed of 18 km/h It travel and streets relardip at 1m/sec2 and come to rest find distance travelled by it?
Answers
Answered by
0
Heres your answer
u=0, v= 18×5/18= 5 m sec and a = 1 m sec^2 t=?
From 1st equation of motion
v-u/t
18-0/1 =t
=18 sec..
So distance will be
s=ut + 1/2 at^2
s= (0×18)+ 1/2 ×1×(18)×(18)
s= 0+9×18×1
s= 162m
Hope it Helps....
Or simply by using (v)^2= (u)^2 +2as
324= 0+2s
324/2=s
162=s
This will be easier...
u=0, v= 18×5/18= 5 m sec and a = 1 m sec^2 t=?
From 1st equation of motion
v-u/t
18-0/1 =t
=18 sec..
So distance will be
s=ut + 1/2 at^2
s= (0×18)+ 1/2 ×1×(18)×(18)
s= 0+9×18×1
s= 162m
Hope it Helps....
Or simply by using (v)^2= (u)^2 +2as
324= 0+2s
324/2=s
162=s
This will be easier...
Similar questions
English,
7 months ago
Hindi,
7 months ago
Geography,
1 year ago
Environmental Sciences,
1 year ago
Social Sciences,
1 year ago
English,
1 year ago