A car is moves from AtoB with uniform speed 40km/hr and moves back to A with uniform speed 60km/hr find the average speed
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Let the distance be x km
X/40+x/60
5x/60
Total distance of botj side be 2x
So average speed
2x/(5x/60)
48m/s
X/40+x/60
5x/60
Total distance of botj side be 2x
So average speed
2x/(5x/60)
48m/s
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