Question

a car is moving 40m due east, turns towards north moves 30m,turns 45° east of north moves 20√2m.find the net displacement

Answer 1

The net displacement required is AD

BF = CE = 20 root2 Cos 45 = 20m

AF = 40 + 20 = 60m

ED = 20 root2 Sin45 = 20m

DF = DE + EF = 20 + 30 = 50m

 

Using triangle ADF and Pythagora’s Theorem

 

AD = root AF 2 + DF2

 

     = root 60^2 + 50^2

 

    = 78.10m

 

Tan DAF = 50/60 = 5/6

 

< DAF = 40 Degrees

 

90 – 40 = 50 degrees

 

The net displacement = 78.10m, 50 Degrees East

Answer 2

Answer:

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