Question

A car is moving along a straight highway with a speed 72 Km/h is brought to rest within the distance 100 m. The retardation of the car is *

5 m/s^2
-10 m/s^2
-2 m/s^2
-5 m/s^2​

Answer 1

Answer:

Hello mate

Explanation:

Pls refers to the attachments.

Answer 2

Answer:

$-2 ms^{2}$

Explanation:

Given :

u = 74 km/h = $72*\frac{5}{18}$ m/s

                   = 20 m/s

v = 0 m/s

distance = 100 m

To find:

Acceleration(retardation) = ?

Solution:

$2as = v^{2} - u^{2}$

$2 * a * 100 = (0)^{2} - (20)^{2}$

$200a = -400$

$a = - \frac{400}{200}$

$a = -2$

∴The retardation is $-2 ms^{2}$

Hope it helps you dear!!!