A car is moving along a straight horizontal road with a speed v_(0) . If the coefficient of friction between the tyres and the road is mu , the shortest distance in which the car can be stopped is
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Answer:
Explanation:
Work done against frictional force equals the kinetic energy of the body.
when a body of mass m, moves with velocity v, it has kinetic energy k=
2
1
mv
2
, this energy is utilized in doing work against the frictional force between the tyres of the car and road.
∴ kinetic energy = work done against friction force
2
1
m
2
=μ mgs
where s is the distance in which the car is stopped and μ is coefficient of kinetic friction.
Given v=v
0
s=
2μg
v
0
2
.
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