Question

A car is moving along a straight horizontal Road with a speed V what is the coefficient of friction between the tyres and the road is mew the shortest distance in which the car can be stopped is

Answer 1

)
Here u = 72 km/h = 20 m/s; v = 0;
a =- ?g = -0.5 × 10 =-5m/s2
As v2 = u1 + 2as,
? s= ((v^2- u^2 ))/2a =((0- (20)^2)/(2× (-5) )=40 m

Answer 2

Answer:

Refer to image

Explanation: