A car is moving along a straight line OP it moves from O to P in 18 seconds and returns from P to Q on 6 seconds where op 360 and OQ = 240 metre. What are the average velocity and average speed of the car in going (a) from O to P and (b) from O to P and back to Q.
Answers
Answer:
➡Average velocity from O to P
= 20 m/s along O to P
➡Average speed from O to P
= 20 m/s
➡Average velocity from O to P and back to Q
= 10 m/s along Q to O
➡Average speed from O to P and Back to Q
= 20 m/s
Explanation:
given that,
A car is moving along a straight line OP
here,
distance from O to P = 360 m
he covers the distance of OP of 360 m
in 18 seconds
also given that,
Q is a point between O and P that
he returns from P to Q
distance of O to Q = 240 m
time taken by the car in returning fromP to Q = 6 seconds
to find average velocity and average speed from
a.) O to P
Average velocity from O to P
here,
distance from O to P = 360 m
time taken = 18 seconds
Average velocity = distance/time
= 360/18
= 20 m/s along OP
Average speed from O to P
distance travelled from O to P = 360 m
time taken = 18 seconds
Average speed = 360/18
= 20 m /s
b.) from O to P and back to Q
Average velocity
here,
displacement = OQ = 240 m
total time taken = 18 + 6
= 24 seconds
Average velocity = 240/24
= 10 m/s along QO
Average speed
total distance travelled = OP + PQ
= 360 + (360 - 240)
= 360 + 120
= 480 m
total time taken = 24 seconds
Average speed = 480/24
= 20 m/s
____________________
➡Average velocity from O to P
= 20 m/s along O to P
➡Average speed from O to P
= 20 m/s
➡Average velocity from O to P and back to Q
= 10 m/s along Q to O
➡Average speed from O to P and Back to Q
= 20 m/s
Answer:
(a) Average velocity from O to P
= 20 m/s along OP
Average speed from O to P
= 20 m/s
(b) Average velocity from O to P and back to Q
= 10 m/s along QO
Average speed from O to P and Back to Q
= 20 m/s
Explanation:
REFER TO ATTACHMENT
sorry for bad handwriting
