a car is moving along a straight road with a uniform acceleration. it passes through two points P and Q separated by a distance with velocity 30km/h and 40km/h respectively the velocity of car midway between P and Q isβ
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Answer:
25β2 km/hr
Explanation:
Let the distance between them is x
now, using the equation v^2 - u^2 = 2as
we can find acceleration of car which come out to be 350/x km/hr^2
now at the mid point,
v^2 - 30^2 = 2(350/x)x
we get v = 25β2 km/hr
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