Question

A car is moving along a straight road with a uniform
acceleration. It passes through two points Pand Q separated
by a distance with velocity 30 km/h and 40 km/h respectively.
The velocity of the car midway between P and Q is
Critical Thinking
(a) 33.3 km/h
(b) 2012 km/h
(c) 2572 km/h
(d) 35 km/h
2o​

Answer 1

Explanation:

Given that

vp = 30km/h

vq = 40km/h

Assume acceleration of the car is a.

PQ = s

Using,

v2 = u2 + 2as

=> 402 = 302 +2as

=> 2as = 700

=> as = 350 ....................(1)

Now, assume velocity of car at a midpoint of PQ is v'.

Then v'2 = vp2 + 2a(s/2)

=> v'2 = 900 + 350 = 1250

=> v' = 35.35 m/s.

Answer 2

Answer:

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Here's ur answer ::::"

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Since, the car is moving from point P to point Q.

The initial velocity of car (V1) = 30 km/h

and the final velocity of car (V2) = 40 km/h

So, To find the velocity between point P and Q.

We will take it as mean velocity,,

.°. »»» Mean velocity (Vmean) = (V1+V2)/2

»» Vmean = (30+40)/2

>> Vmean = 70/2

.°. «» Vmean = 35 km/h

Thus, The velocity of car between points P and Q is 35 km/h...

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