a car is moving along a straight road with a uniform accelration . it passes through 2 points P and Q separated by a distance with velocity of 30km/h and 40 km/h respectively. the velocity of car midway between P and Q .
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distance between p and q
v square - u square =2as
700*5/18=2as
700*5/36a=s........1
distance at mid point
s/2=v1square - 30*5/18a..........2
from 1 and 2
700*5/72a=vsquare -30*5/18a
1025a/18a =v 1square
v1=7.54a m/s
v square - u square =2as
700*5/18=2as
700*5/36a=s........1
distance at mid point
s/2=v1square - 30*5/18a..........2
from 1 and 2
700*5/72a=vsquare -30*5/18a
1025a/18a =v 1square
v1=7.54a m/s
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