a car is moving along a straight road with uniform acceleration it passes through two points P and Q separated by distance with velocity 30 km per hour and 40 km per hour respectively the velocity of car Midway between P and Q is
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"Given that
vp = 30km/h
vg = 40km/h
Assume acceleration of the car is a.
PQ = s
Using, v2 = u2 + 2as
=> 402 = 302+2as
=> 2as = 700 => as = 350
Now, assume velocity of car at a midpoint of PQ is V.
Then V2 = vp2 + 2a(s/2)
=> V2 = 900 + 350 = 1250
=> V = 35.35 m/s.
"
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Hope it helps you. All the best.
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