Science, asked by priyavarma726pd2wte, 1 year ago

a car is moving along a straight road with uniform acceleration it passes through two points P and Q separated by distance with velocity 30 km per hour and 40 km per hour respectively the velocity of car Midway between P and Q is

Answers

Answered by aqibkincsem
101

"Given that

vp = 30km/h

vg = 40km/h

Assume acceleration of the car is a.

PQ = s

Using, v2 = u2 + 2as

=> 402 = 302+2as

=> 2as = 700 => as = 350

Now, assume velocity of car at a midpoint of PQ is V.

Then V2 = vp2 + 2a(s/2)

=> V2 = 900 + 350 = 1250

=> V = 35.35 m/s.

"

Answered by Gokul2003g
116

Hope it helps you. All the best.

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