A car is moving along a straight road with uniform acceleration it passes through two points p and q separated by a distance with velocities 30 km/h and 40km/h respectively the velocity of car midway between p and q is
Answers
Answered by
6
Let the distance between p and q be s. Also , let the uniform acceleration be a.
While moving from p to q, the equation of motion, v^2 - u^2= 2as will become
(40)^2–(30)^2= 2as……………………..(1)
If velocity at mid point between p and q is v', then,
v'^2-(30)^2=as……………………….(2)
Therefore,
2v'2–2(30)^2= 2as………………….(3)
From equations (1) and (3),
(40)^2 -(30)^2=2v'^2–2(30)^2
Or
1600–900+1800=2v'^2 or
1250=v'2 , then
v'=35.35 km/hr
While moving from p to q, the equation of motion, v^2 - u^2= 2as will become
(40)^2–(30)^2= 2as……………………..(1)
If velocity at mid point between p and q is v', then,
v'^2-(30)^2=as……………………….(2)
Therefore,
2v'2–2(30)^2= 2as………………….(3)
From equations (1) and (3),
(40)^2 -(30)^2=2v'^2–2(30)^2
Or
1600–900+1800=2v'^2 or
1250=v'2 , then
v'=35.35 km/hr
Similar questions