A car is moving along straight high way with a speed of 60km/h brought to stop with a distance of 200meters.What is the acceleration of the car is assumed to be uniform motion how long will it take to stop the car?.
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u=60km/hr= 60×5/18= 25m/s
v=0
s= 200m
v²-u²=2as
a= v²-u²/2s
a= 0²-25²/2×200= -625/400= -25/16= -1.5625m/s²
t=v-u/a = 0-25 / 25/16 = 16seconds
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