A car is moving at 10m/s when the brakes are applied and it comes to rest in 5 s. What is the retardation produced.
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Answers
Answered by
1
Answer:
x=10t
0<t5sec for t=5sec,
x1=50m
0=10−a(10−5)⇒a=2m/s2
x−x1=10(t−5)−12a(t−5)2(5<t<10)
⇒x=50+10t−50−t2−25+10t
x=−t2+20t−25
at t=10,x2=75m for t>10sec
x = 75 m`.
Explanation:
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Answered by
0
Answer:
Explanation:
given,
u = 10m/s
v = 0m/s
t = 5s
we know, a = (v-u)/t = -10/5 = -2m/s^2
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