Question

a car is moving at 36 m/s after it has accelerated at a rate of 4 m/s squared for 7 seconds. What was the car's initial velocity?

Answer 1

Answer:

8m/s

Explanation:

a = 4m/s^

t = 7s

v = 36 m/s

u = ?

now ;

a =( v - u)/t

4 = (36 - u )/7

28 = 36 - u

u = 36 - 28

u = 8m/s

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Answer 2

Answer:

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Explanation:

Given

Final velocity(v) = 36m/s

Acceleration (a) = 4m/s

Time (t) = 7 seconds

Initial velocity (u)= ?

Formula:

v=u+at

u=v-at

u=36-4*7

u=36-28

u=8m/s

therefore initial velocity(u)=8m/s