Question

A car is moving at 45 km/hr.A constant force acts on the car for 10 sc .So that it's velocity becomes 63 km/hr .The distance travelled by car during this interval of 10 sec is :

Answer 1

Answer:

Explanation:

initial velocity of car is 12.5m/s   .......(to convert km/hr into m/s divide given                                       value by 3.6)

final velocity is 17.5m/s

distance covered  is s

t =10 s

a is acceleration so

(v-u)/t =a

(17.5-12.5)/10 =a

0.5 =a

now v^2-u^2 =2as

145/2x0.5 = s

s=145m