Question

a car is moving at a rate of 40 km/hr.How gar does it move when it stops after 5 seconds?​

Answer 1

U=initial speed=72km/h=20 m/sec.

v=final speed  =0 km/h

time=t= 5 sec.

v=u+at

v-u=at= v-u/t=a

-20/5= -4 m/sec^2 = deacceleration

now using the eqn:-

S=ut+1/2 a

S=20*5 +  (-4) * 5*5

S=100 - 50 =50