Question

A car is moving at a rate of 72 km/hr. how far does the car move when it stops after 4 second

Answer 1

Answer:

V=(72 km/hr)(hr/60 min)(min/60 sec)(1000 m/km)= 20 m/sec

If the car stops in 4 seconds, use v(t)-v(0)+at to calculate the acceleration:

a=[v(4)-v(0)]/4=[0–20]/4=-5 m/sec^2 (a decelleration)

x=0.5at^2=0.5(5)(4)^2= 40 m

Explanation:

Answer 2

V=(72 km/hr)(hr/60 min)(min/60 sec)(1000 m/km)= 20 m/sec

If the car stops in 4 seconds, use v(t)-v(0)+at to calculate the acceleration:

a=[v(4)-v(0)]/4=[0–20]/4=-5 m/sec^2 (a decelleration)

x=0.5at^2=0.5(5)(4)^2= 40 m