A car is moving at a speed of 40m/s on a circular track of radius 400m. This speed is increasing at the rate of 3 m/s^2 . The acceleration of car is _______???
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circumference of a circular track =2 pi r
2×22÷7×400=2514.2857142857
using v^2 =u^2+2as
3^2=40^2+2×a×2514.2857142857
9= 6628.574285714a
a=6628.574285714÷9= 0.001357758
there fore the acceleration of the car is 0.001357758 m per sec ^2
2×22÷7×400=2514.2857142857
using v^2 =u^2+2as
3^2=40^2+2×a×2514.2857142857
9= 6628.574285714a
a=6628.574285714÷9= 0.001357758
there fore the acceleration of the car is 0.001357758 m per sec ^2
retoolsr08:
but the answer is 5m/s^2
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