Question

A car is moving at a speed of 90whole 2/8.
km/hr. Find how much distance will it cover in 9/18hrs​.

#No sham Answer
​

Answer 1

Answer :-

• The car will cover 45.125 km in 9/18 hours.

To find :-

• The distance the car will cover in 9/18 hours.

Solution :-

• Here, it is given that a car is moving at a speed of 90 whole 2/8 km/hr. We have to find the distance it will cover in 9/18 hours.

We know that :-

$\underline{ \boxed{\sf Distance = Speed \times Time}}$

Here,

• Speed = 90 whole 2/8 km/hr.
• Time = 9/18 hours.

Therefore,

$\longrightarrow\rm Distance = 90 \: \dfrac{2}{8} \times \dfrac{9}{18}$

$\rm \longrightarrow Distance = \dfrac{722}{8} \times \dfrac{9}{18}$

Cancelling the numbers,

$\longrightarrow \rm Distance = \dfrac{361}{8} \times \dfrac{1}{1}$

$\longrightarrow \rm Distance = \dfrac{361}{8}$

$\longrightarrow \rm Distance = 45.125 \: km$

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Some more related formulae :-

$\boxed{\bigstar \: \mathfrak{ Speed = \dfrac{Distance}{Time}}}$

$\boxed{\bigstar \: \mathfrak {Time = \dfrac{Distance}{Speed}}}$

Answer 2

Question :

A car is moving at a speed of 90whole 2/8 km/hr. Find how much distance will it cover in 9/18hrs

Solution :

$\sf Speed \: of \: the \: car \rarr 90\frac{2}{8}km \: {h}^{ - 1}$

Distance covered in 9/18 hrs = ?

So as per our formula we know that

Distance = Speed × Time

$\sf{distance}=90\frac{2}{8} \times \frac{9}{18}$

$\sf{distance} = 90 \cancel{\frac{2}{8} } \times \frac{9}{18}$

$\sf{distance} = \frac{361}{4} \times \frac{9}{18}$

$\sf{distance} = \frac{361}{ \cancel{4}} \times \cancel{\frac{9}{18} }$

$\sf{distance = \frac{361}{8} }$

$\sf{distance} = 45.125 \: km$

Hence distance covered in 9/18 hrs is 45.125 km