Question

a car is moving at a uniform speed 72km/hr the diver sees a child at a distance of 50m​

Answer 1

Answer:

$- 4 {m}/ {s}^{2}$

Explanation:

I assume you require the rate of deceleration.

${v}^{2} - {v_{0} }^{2} = 2 \times a \times d$

${0}^{2} - {20}^{2} = 2 \times a \times 50 \\ - 400 = 100a \\ a = - 4{m}/{s}^{2} }$