A car is moving at a velocity of 54 km/h ^-1 . Suddenly brakes are produced a declaration of 6m/^2 , find the distance covered by the car before coming to rest ?
Pls answer fast
Answers
Answered by
3
Answer:
u = 54 km/h= 54× 1000/3600= 15 m/s
v= u + at
0= 15 + 6.t
6.t = -15
t = -15/6= -5/2
So distance covered in 5/2 seconds
S = ut + 1/2 at²
= 15× 5/2 + 1/2 × 6 × 25/4
= 75/2 + 75/4
= (75× 3)/ 4
=225/ 4
= 56.25 m
Similar questions