A car is moving at a velocity of 54Kmh ^ -1. Suddenly driver applies brakes and produces a deceleration of 6m/s2. Find the distance covered by the car before coming to rest.
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Given:-
Initial velocity of the car(u)=54km/h
=>54×5/18
=>3×5
=>15m/s
Deceleration=6m/s
Thus,acceleration(a) is -6m/s²
Final velocity(v)=0 (as the car finally stops after the application of brakes)
To find:-
Distance covered by the car be fore coming to rest(s).
Solution:-
We wil use here the third equation of motion i.e.----
Thus,the distance covered by the car is 18.75m.
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